A Problem In Dynamics Poem Rhyme Scheme and Analysis

Rhyme Scheme: AABC DDEFGGHIJJ IIEEKKLKAA EEFFEEJJEEMJNAJJOOPP QQ BBGGJJRREEGGOOEESS

An inextensible heavy chainA
Lies on a smooth horizontal planeA
An impulsive force is applied at AB
Required the initial motion of KC
-
Let ds be the infinitesimal linkD
Of which for the present we ve only to thinkD
Let T be the tension and T dTE
The same for the end that is nearest to BF
Let a be put by a common conventionG
For the angle at M twixt OX and the tensionG
Let Vt and Vn be ds s velocitiesH
Of which Vt along and Vn across it isI
Then Vn Vt the tangent will equalJ
Of the angle of starting worked out in the sequelJ
-
In working the problem the first thing of course isI
To equate the impressed and effectual forcesI
K is tugged by two tensions whose difference dTE
Must equal the element's mass into VtE
Vn must be due to the force perpendicularK
To ds s direction which shows the particularK
Advantage of using da to serve at yourL
Pleasure to estimate ds s curvatureK
For Vn into mass of a unit of chainA
Must equal the curvature into the strainA
-
Thus managing cause and effect to discriminateE
The student must fruitlessly try to eliminateE
And painfully learn that in order to do it heF
Must find the Equation of ContinuityF
The reason is this that the tough little elementE
Which the force of impulsion to beat to a jelly meantE
Was endowed with a property incomprehensibleJ
And was given in the language of Shop inexten sibleJ
It therefore with such pertinacity odd defiedE
The force which the length of the chain should have modifiedE
That its stubborn example may possibly yet recallM
These overgrown rhymes to their prosody metricalJ
The condition is got by resolving againN
According to axes assumed in the planeA
If then you reduce to the tangent and normalJ
You will find the equation more neat tho less formalJ
The condition thus found after these preparationsO
When duly combined with the former equationsO
Will give you another in which differentialsP
When the chain forms a circle become in essentialsP
No harder than those that we easily solveQ
In the time a T totum would take to revolveQ
-
Now joyfully leaving ds to itself aB
Ttend to the values of T and of aB
The chain undergoes a distorting convulsionG
Produced first at A by the force of impulsionG
In magnitude R in direction tangentialJ
Equating this R to the form exponentialJ
Obtained for the tension when a is zeroR
It will measure the tug such a tug as the heroR
Plume waving experienced tied to the chariotE
But when dragged by the heels his grim head could not carry aughtE
So give a its due at the end of the chainG
And the tension ought there to be zero againG
From these two conditions we get three equationsO
Which serve to determine the proper relationsO
Between the first impulse and each coefficientE
In the form for the tension and this is sufficientE
To work out the problem and then if you chooseS
You may turn it and twist it the Dons to amuseS

James Clerk Maxwell



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